300 Gm Of Water At 25 C Is Added To

300 Gm Of Water At 25 C Is Added To. Web300 gm of water at 25oCis added to 100 gm of ice at 0oC. The final temperature of the mixture is A −35 oC B −25 oC C −5oC D oC Medium Answer Correct option is A −35 oC. Web300 gm of water at 25 oC is added to 100 gm of ice at 0 oC. The final temperature of the mixture is A − 35oC B − 25oC C −5 oC D oC Medium Solution Verified by Toppr Correct.

WebThis is asking you to look at the heat transfer between a hotter substance and a colder substance, and the hotter transfers to the colder. I would expect the result. Web300g of water at 25 ∘C is added to 100g of ice at 0 ∘C. The final temperature of the mixture is Medium Solution Verified by Toppr Hot body (Water) mass of water =300g. Web300 gm of water at 25 −0C is added to 100 gm of ice at 0 −0C. The final temperature of the mixture is - A − 35−0C B − 25−0C C −5 −0C D −0C Medium Solution Verified by Toppr.

300 gm of water at 25 C is added to 100 gm of ice at 0 C The final

Web(i) The heat released by 300g of water at 25 ∘ C to change its temperature to 0 ∘ C = mcΔT = 300×4.2×25 = 31,500J…. (ii) Since the energy in eq. (ii) is less than of eq (i) therefore.

Web300 gm of water at 25ºC is added to 100 gm of ice at 0ºC. The final temperature of the mixture is (A) – 5/3 ºC (B) – 5/2 ºC (C) – 5ºC (D) 0ºC simple harmonic. WebAns:- Hot body (Water) mass of water =300g temparature= 25°c Change in temperature = (25-x) Let us suppose 'x' is the final temperature Cold body (Ice) mass of. Webanswered 300 gm of water at 25°C is added to 100 gm of ice at O°C. The final temperature of the mixture is Advertisement Answer 1 person found it helpful dilipniroula.

WebQ: 300 gm of water at 25°C is added to 100 g of ice at 0°C. The final temperature of the mixture is (a) -5/3 °C (b) -5/2 °C (c) – 5 °C (d) 0 °C Click to See. Webnt300 gm of water at 25c is added to 100 gm of ice at 0C. THE FINAL TEMP OF MIXTURE ISn Open in App Solution Suggest Corrections 4 Related Video Download BYJU'S The. Web11. 300 gm of water at 25°C is added to 100 gm of ice at 0°C. The final temperature of the mixture is (1) C (3) -5°C (4) 0°C Solution Verified by Toppr Solve any question of.

WebTotal mass of water after mixing would be $300gm + 100gm = 400gm$. Amount of water again converted into ice would be given by, $m = \dfrac { {470}} {. Web300 gm of water at 25 −0C is added to 100 gm of ice at 0 −0C. The final temperature of the mixture is - A − 35−0C B − 25−0C C −5 −0C D −0C Medium Solution Verified by Toppr. Web300gm of water at 25oC is added to 100gm of ice at 0oC. Final temperature of the mixture is: A −35 °C B −25 °C C −5°C D 0°C Difficulty level:medium Viewed by:.

300 Gm Of Water At 25 C Is Added To. 300 Gm Of Water At 25 C Is Added To, 300 grams of water at `25^@ C` is added to 100 grams of ice at `0^@ C.` The final temperature, 12.18 MB, 08:52, 2,803, Doubtnut, 2020-07-05T06:45:26.000000Z, 3, 300 gm of water at 25 C is added to 100 gm of ice at 0 C The final, www.meritnation.com, 1023 x 633, jpeg, Web300 gm of water at 25oCis added to 100 gm of ice at 0oC. The final temperature of the mixture is A −35 oC B −25 oC C −5oC D oC Medium Answer Correct option is A −35 oC. Web300 gm of water at 25 oC is added to 100 gm of ice at 0 oC. The final temperature of the mixture is A − 35oC B − 25oC C −5 oC D oC Medium Solution Verified by Toppr Correct. WebThe formula for specific heat looks like this: c = \frac Q m \Delta T c = mΔT Q. Q Q is the amount of supplied or subtracted heat (in joules), m m is the mass of., 20, 300-gm-of-water-at-25-c-is-added-to, Books and News